Math is very confusing. Again I need some help with math. I need help with: Factoring a quadratic with leading coefficient greater than 1 The Problem: 6x^2+13x+6
No its X to the squared power. I already tried and I got the answer wrong. Okay let me try again: 3y^2(y to the second power)-16y+16 Okay um... 4 goes into 16 and 1y might work. Let me see um... (1y+4)(4y+4)
FoxyMomma gave the right answer. Step-wise: 6x^2+13x+6 Method I'm using: Breaking Mid-term (In this case = 13x) For that: Sum 13 Product 36 (Multiply 1st term and Last term) +9 and +4 is the correct combination. Since 9*4=36, 9+4=13. So 6x^2+9x+4x+6 3x(2x+3)+2(2x+3) - Factorization (3x+2)(2x+3) Factorization
(I was asking about the second term, 13x, but FoxyMama got there first with the answer to the one you asked)
That isn't correct either. Um let me see uh.... Nevermind. Let me try another: 2z^2-3z-14 Tow times a number to the second power minus three times a number minus fourteen So let me see: (2z-7)(3z-7)
Thanks FM. But I'm just going to give up on this. Its impossible for me to comprehend math. The funny thing is that as I have stated before English is not my native langauge, but I do better in English then math. But all the other foreign kids are better at math then I am.
Try splitting the middle term or multipling first term by last term (excluding exponents) and then factoring from there.
Okay I'll try this one: W divided by 6wx divided by 9w divided by 4x My answer: 2 divided by 27/w 2/27w
Leaka: Start by factoring the first term, and the third term. Those factors are multipliers (coefficients) for the first and second terms onf your binomials in most of these problems. 2 can only be factored as 2*1 (in whole numbers), and 14 can either be 2*7 or 14*1 so your x terms will probably be x and 2x, and your x^0 terms (constants) will probably be 1 and 14 or 2 and 7 Because the first term is +, the xterms will both be positive (they could also bot be negative, but in that case we could FORCE them both to be positive. Likewise, because the third term is positive, the constants will either be both positive or both negative. In this case, we cannot force them, because we have already forced the x terms - you can only force once. BUT - because the signs ARE the same, and the second term is positive, we know that both our constants will be positive. So these are our most likely possibilities: (x+1)(2x+14) (x+14)(2x+1) (x+2)(2x+7) (x+7)(2x+2) Try each of them out to see which one gives the right center term. That's how most of these are soved by factoring, which I assume is the method you are expected to use at this stage. There are other methods for solving more difficult factoring problems, but you should master this one.
The other hint is that the middle term is the sum of the cross-products. You'll start to see the pattern with practice though,so I don't want to say too much more than that. "Give a man a fish, you feed him for a day. Teach a man to fish, you feed him for life."
w divide sign 9w 6wx 4x w times sign (.) 4x 6wx 9w w . 2x 2.3wx 3.3w =2 27w Next one: An 82 degree line is attached to a kite. When the kite has pulled its line taut, the angle of the elevation to the kite is 52 degrees . Find the height of the kite. Round your answer to the nearest hundredth.
Well I can't put the triangle down. It goes something like: Sin= o 82 82 x 52 degrees 52 degrees= .7880 82 X .7880= 64.616 =64.62
I believe you copied the problem incorrectly. This question makes more sense if 82 is a linear measure instead of degrees. If that is the case, your solution is correct.
You don't go to FLVS do you? Cause they tend to give you the wrong answer. And I just covered this for a second time(going from a Private School to a Public is not the best idea) and I still can't remember it, and if I did I'd probably give you the wrong answer cause I wouldn't know what the hell I was doing, sorry.